First the all, it"s CuSO4*5H2O (notice the capital "O" in the an initial part of the formula). The compound is referred to as copper(II) sulfate pentahydrate, and if we wish to discover the percent by massive of water, we need to discover the molar fixed of the hydrate first.

Cu = 63.55 g/mol

S = 32.07 g/mol

O x 4 = 16.00 g/mol x 4 = 64.00 g/mol

H2O x 5 = 18.02 g/mol x 5 = 90.10 g/mol

Now add them every together and you gain a molar massive of 249.72 g/mol

Of that 249.72 grams, 90.10 grams is water, so to uncover the percent by mass that is water, merely divide 90.10 g through 249.72 g and multiply the result by 100%:

90.10 g / 249.72 g x 100% = 36.08% water


Wiki User

∙ 8y ago
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