Question 1 (00000001A0402100, variation No. 70): B.False FeedbackThe ions are Ca2+and CO32-. Thesimplest combination with a zero full charge is among each. To it is in able toanswer this form of question on a test, you need to have memorized the namesand recipe of polyatomic ions (unless her teacher permits you come consult alist of names and formulas throughout the test).Given the name of a compound v a polyatomic ion, you can write the formulaas follows:1. Number out the formulas of the cation and also anion.Note that the name of the cation is always statedfirst.2. Find the simplest combination of cations and anions the would provide a zero total charge.NOTE the if friend need an ext than among a polyatomic ion in the formula, youenclose the entire polyatomic ion in parentheses.




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Question 2 (00000001A0402300, sports No. 53): FeSO4 The completed passage is:The formula the iron(II) sulfate is FeSO4. FeedbackThe cation is Fe2+.The anion is SO42-.You must put together ONE cation (2+) and also ONEanion (2-). To have the ability to answer this kind of questionon a test, you require to have actually memorized the names and also formulas of polyatomic ions(unless your teacher allows you come consult a perform of names and also formulas duringthe test).Given the surname of a compound with a polyatomic ion, you have the right to write the formulaas follows:1. Figure out the recipe of the cation and anion.Note the the name of the cation is always statedfirst.2. Uncover the simplest combination of cations and anions the would give a zero full charge.NOTE that if friend need much more than one of a polyatomic ion in the formula, youenclose the whole polyatomic ion in parentheses.


Question 3 (00000001A0402301, sports No. 57): Ag3PO4 The completed i is:The formula of silver phosphate is Ag3PO4.FeedbackThe cation is Ag+. The anion is PO43-. You have to puttogether 3 cations (+) and also ONE anion (3-). To have the ability to answer this type of concern on a test,you need to have memorized the names and formulas of polyatomic ions (unlessyour teacher allows you to consult a perform of names and formulas throughout thetest).Given the surname of a compound with a polyatomic ion, you can write the formulaas follows:1. Number out the recipe of the cation and anion.Note the the name of the cation is always statedfirst.2. Uncover the simplest combination of cations and also anions that would offer a zero full charge.NOTE that if girlfriend need more than one of a polyatomic ion in the formula, youenclose the whole polyatomic ion in parentheses.




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Question 4 (00000001A0402303, variation No. 28): sodiumcarbonate The completed passage is:The formula of salt carbonate is Na2CO3.FeedbackThe cation is sodium, Na+. The anion iscarbonate, CO32-. Tobe able come answer this type of concern on a test, you require to have actually memorizedthe names and formulas of polyatomic ion (unless her teacher enables you toconsult a list of names and formulas during the test).The surname of one ionic link is simply the name of the cation,followed by the surname of the anion. Given the formula the a compound, you deserve to tell that it is ionic if that startswith a steel or ammonium. When you have established the compound as ionic,anything in parentheses must be a polyatomic ion. If the metal is recognized to formmore than one cation, you require to number out thecharge the the cation from the charge of the anion(then point out the charge of the cation in Romannumeral). The total charge because that cations and anions inthe formula need to be zero.


Question 5 (00000001A0402304, sports No. 30): ammoniumphosphate The completed i is:The formula of ammonium phosphate is (NH4)3PO4. FeedbackThe cation is ammonium, NH4+.The anion is phosphate, PO43-.To have the ability to answer this kind of question on a test, you must havememorized the names and also formulas that polyatomic ion (unless her teacher allowsyou come consult a perform of names and formulas during the test).The name of one ionic link is simply the surname of the cation,followed by the surname of the anion. Provided the formula the a compound, you can tell the it is ionic if the startswith a steel or ammonium. As soon as you have figured out the compound together ionic,anything in parentheses need to be a polyatomic ion. If the metal is well-known to formmore than one cation, you need to figure out thecharge that the cation native the charge of the anion(then point out the fee of the cation in Romannumeral). The total charge for cations and also anions inthe formula must be zero.