The electron construction for silver- (Ag) is based top top the place meant of silver- in the fifth row of the routine table in the 11th shaft of the periodic table or the 9th column of the transition metal or d block. As such th electron configuration for silver must finish as #4d^9#,

#1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^9#

This notation can be written in main point notation or noble gas notation by replacing the #1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6# through the noble gas .

# 5s^2 4d^9#

For some of the change metals they will actually transfer an s electron to complete the d orbital, make silver,

# 5s^1 4d^10#

I hope this was helpful.SMARTERTEACHER




You are watching: What is the electron configuration for silver

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Stefan V.
Oct 30, 2015

#"Ag: " <"Kr"> 4d^10 5s^1#




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Explanation:

Silver, #"Ag"#, is situated in period 5, group 11 of the routine table, and also has an atom number equal to #47#.

This tells you the a neutral silver atom will have actually a full of #47# electrons neighboring its nucleus.

Now, you need to be a tiny careful v silver due to the fact that it is a transition metal, which means that the populated d-orbitals are actually lower in energy 보다 the s-orbitals that belong to the highest power level.

So, here"s just how silver"s electron configuration would certainly look if it complied with the Aufbau principle to the letter

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(blue)(4s^2 4p^6) color(red)(3d^10) 5s^2 4d^9#

Now, for the energy level #n#, the d-orbitals that belong to the #(n-1)# energy level are lower in energy 보다 the s and p orbitals the belong come the #n# power level.

This way that girlfriend will need to switch the 3d orbitals ~ above one hand, and the 4s and 4p orbitals ~ above the other.

This will acquire you

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 5s^2 4d^9#

Now execute the very same for the 4d and also 5s orbitals

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 4d^9 5s^2#

The point to remember here is the in silver"s case, the 4d orbitals will certainly be completely filled. That means that girlfriend won"t have actually two electrons in the 5s orbital, due to the fact that one will be preserved in the lower 4d orbitals.

This means that the electron construction of silver will be

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 4d^10 5s^1#

Using the noble gas shorthand notation will acquire you

#"Ag: " overbrace(1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6))^(color(green)(<"Kr">)) 4d^10 5s^1#