The electron construction for silver- (Ag) is based top top the place meant of silver- in the fifth row of the routine table in the 11th shaft of the periodic table or the 9th column of the transition metal or d block. As such th electron configuration for silver must finish as #4d^9#,

#1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^9#

This notation can be written in main point notation or noble gas notation by replacing the #1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6# through the noble gas

#

For some of the change metals they will actually transfer an s electron to complete the d orbital, make silver,

#

I hope this was helpful.SMARTERTEACHER

You are watching: What is the electron configuration for silver

Answer attach

Stefan V.

Oct 30, 2015

#"Ag: " <"Kr"> 4d^10 5s^1#

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Explanation:

*Silver*, #"Ag"#, is situated in period 5, group 11 of the routine table, and also has an atom number equal to #47#.

This tells you the a *neutral* silver atom will have actually a full of #47# electrons neighboring its nucleus.

Now, you need to be a tiny careful v silver due to the fact that it is a *transition metal*, which means that the populated **d-orbitals** are actually *lower in energy* 보다 the **s-orbitals** that belong to the highest power level.

So, here"s just how silver"s electron configuration would certainly look if it complied with the *Aufbau principle* to the letter

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(blue)(4s^2 4p^6) color(red)(3d^10) 5s^2 4d^9#

Now, for the energy level #n#, the **d-orbitals** that belong to the #(n-1)# energy level are *lower in energy* 보다 the s and p orbitals the belong come the #n# power level.

This way that girlfriend will need to switch the **3d** orbitals ~ above one hand, and the **4s** and **4p** orbitals ~ above the other.

This will acquire you

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 5s^2 4d^9#

Now execute the very same for the **4d** and also **5s** orbitals

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 4d^9 5s^2#

The point to remember here is the in silver"s case, the **4d** orbitals will certainly be **completely filled**. That means that girlfriend won"t have actually two electrons in the **5s** orbital, due to the fact that one will be preserved in the lower 4d orbitals.

This means that the electron construction of silver will be

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 4d^10 5s^1#

Using the noble gas shorthand notation will acquire you

#"Ag: " overbrace(1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6))^(color(green)(<"Kr">)) 4d^10 5s^1#