Factors the 24 space basically the number that division it evenly or precisely without leaving any kind of remainder i.e if a number divides 24 v a remainder that zero, then the number is dubbed a factor.

All Factors: 1, 2, 3, 4, 6, 8, 12 and also 24.

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Prime factors: 2, 3.Factors in pairs: (1,24), (2,12), (3,8), (4,6),(6,4),(8,3),(12,2).

Prime administrate of 24

Prime factorization is a method of “expressing” or finding the offered number as the product of element numbers. If a number occurs an ext than when in prime factorization, that is usually expressed in exponential form to make it much more compact.

The prime factorization comes out to be: 2 × 2 × 2 × 3 = 23× 3.

Prime factorization of 24 through Upside-Down division Method

Upside-Down department is among the approaches used to perform the prime factorization of different numbers.

In this method, you will divide a offered “composite” number evenly by the numerous prime numbers(starting native the smallest) it rotates it it s okay a prime number.


It is called Upside-Down Division because the price is flipped upside down.

Here, 24is an even number. So the is undoubtedly divisible by 2 with no remainder.Thus, 2 is its smallest prime factor.

And we gain 24÷ 2 = 12. Now discover the prime determinants of the obtained quotient.

Repeat action 1 and also Step 2 until we gain a result of element number as the quotient. Here, 12is the quotient.

12÷ 2 = 6. Here, 6 is the quotient.Now uncover the prime components of the 6.

6÷ 2= 3. Here, 3 is the prime number.

So we have the right to stop theprocess.

So, prime factorization with upside-down division method comes the end to be:2× 2× 2× 3 = \(2^3 \times 3\).

Prime factorization of24 by variable Tree Method

The aspect tree method is another method for producing the prime factorization and also all determinants of a given number.

To use this technique for a number x,

Firstly consider two components say a,b that x such the a*b is same to x and also at least one of castle (a, b) is a prime variable say a.

Then take into consideration two components of b speak c, d such the again at least one of lock is a prime factor. This process is repeated until both the factors are element i.e if we obtain both the determinants as element at any type of step, we avoid the process there.

Following is the element tree the the offered number.

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Here we can acquire the element factorisation of 24 together 2 * 2 * 2 * 3 and the 2 prime determinants are 2, 3


What is the sum of the determinants of 24?

Sum the all determinants of the required number = (23 + 1 – 1)/(2 – 1) × (31 + 1 – 1)/(3 – 1) = 60

What are the common Factors the 24 and also 21?

Since, the components of 24 room 1, 2, 3, 4, 6, 8, 12, 24 and also the determinants of 21 room 1, 3, 7, 21.Hence, <1, 3> room the typical factors of 24 and 21.