I think they are asking for the total variety of electrons for each of the atoms when they are in the structureSo if you attract out the framework, you have actually 5 bonds on P which implies 10 electrons (5 are coming from P and also 5 are covalently shared from O)and also for O, each oxygen has actually the 8 electrons in full when it is part of this structure
I agree the Q is a little bit confmaking use of as worded however if they are sticking with the correct answer (which renders no mention of subshells??), illustration the Lewis structure on inquiries like these can make them less complicated to solve effectively. Here we deserve to view tright here are 10 total valence electrons around P and 8 complete valence electrons around each Oxygen.
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The answer claims tright here are 2 s-electrons, 6 p-electrons, and 2 d-electrons. I understand also just how you get 10 valence electrons total, however have the right to someone please define wright here the 2 d electrons come from for the P in PO_4 (3-)?
This is just how I believed around it.Fact: All elements in period three and also listed below on the routine table have the right to accept electrons into their d subshell.Process:The electron configuration (shorthand) for P is
Don"t Get Psyched: How would you know that oxygen will certainly add 5 valence electrons through bonding without drawing a Lewis structure, or is that your thinking after seeing there are 5 bonds to P (thus, 10 electrons in full for P)? I simply wanted to know if I am absent somepoint in your logic. Many type of thanks!
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