first calculation the mole of # CO2 # = 100/44 = 2.27 molnow variety of electrons in # CO2 # are obtained by adding total electron in every of the three atoms i.e. 2 O and one C = 6+8+8 = 22thus one mole the # CO2 # has # 22 * 6.022 * 10^23 # electrons and also 2.27 mol has # 2.27 * 22 * 6.022 * 10^23 # electrons = # 301.1 * 10^23 # electron




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The an initial thing come do here is to calculation the number the moles of carbon dioxide present in her sample. To execute that, use the compound"s molar mass

#100 color(red)(cancel(color(black)("g"))) * "1 mole CO"_2/(44.0color(red)(cancel(color(black)("g")))) = "2.27 mole CO"_2#

Next, usage Avogadro"s constant to number out the variety of molecules the carbon dioxide current in the sample.

#2.27 color(red)(cancel(color(black)("moles CO"_2))) * (6.022 * 10^(23)color(white)(.)"molecules CO"_2)/(1color(red)(cancel(color(black)("mole CO"_2))))#

# =1.37 * 10^(24)# #"molecules CO"_2#

Now, every molecule that carbon dioxide includes

one atom of carbon, #1 xx "C"#two atoms of oxygen, #2 xx "O"#

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This method that your sample contains

#1.37 * 10^(24)color(red)(cancel(color(black)("molecules CO"_2))) * "1 atom C"/(1color(red)(cancel(color(black)("molecule CO"_2))))#

# = 1.38 * 10^(24)# #"atoms that C"#

and

#1.37 * 10^(24) color(red)(cancel(color(black)("molecules CO"_2))) * "2 atoms O"/(1 color(red)(cancel(color(black)("molecule CO"_2))))#

# = 2.74 * 10^(24)# #"atoms that O"#

Next, seize a regular Table and look for the atomic numbers that the 2 elements. You will certainly find

#"For C: " Z = 6#

#"For O: " Z = 8#

As girlfriend know, a neutral atom has actually equal numbers the protons situated inside that is nucleus and electrons surrounding the nucleus.

Therefore, you have the right to say that every atom that carbon will contain #6# electrons and also every atom that oxygen will certainly contain #8# electrons.

This means that you will certainly have

#"total no. The e"^(-) = overbrace(6 * 1.37 * 10^(24))^(color(blue)("coming from C atoms")) + overbrace(8 * 2.74 * 10^(24))^(color(purple)("coming indigenous O atoms"))#

#"total no. Of e"^(-) = (8.22 + 21.92) * 10^(24)#

which it s okay you

#color(darkgreen)(ul(color(black)("total no.

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The e"^(-) = 3 * 10^(25))))#

The answer need to be rounded come one significant figure, the variety of sig figs you have actually for the mass of carbon dioxide.