The International room Station provides 15.65 changes per work in its orbit around the earth. Suspect a one orbit, how high is this satellite above the surface ar of the earth?

Considering that

the frequency of transformation of the international space spation roughly Earth is

and so its orbital duration is

*

Now we have the right to use Kepler's third law to find the radius that the orbit of the space station, r. Knowning that the planet mass is

*
Kepler's third law deserve to be composed as

*

where G is the gravitational constant. Re-arranging the formula and using the value of T we discovered previously, we find the orbit radius:

*

which synchronizes to r=6750 km.

You are watching: The international space station makes 15.65 revolutions per day in its orbit around the earth

This is the radius of the orbit measured indigenous the facility of Earth. To find the distance of the space station indigenous the Earth's surface, we should subtract the Earth's radius, R=6370 km, and we find:

*

So, the an are station is roughly 380 km above Earth's surface.


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