Draw the molecule by placing atom on the grid and connecting them through bonds. Incorporate all hydrogen atoms and also nonbonding electrons.

You are watching: Make a sketch of the following molecule n2

**Part B**

Make a sketch of the following molecule: N2H2 (skeletal framework HNNH).

Draw the molecule through placing atom on the grid and connecting them with bonds. Incorporate all hydrogen atoms and also nonbonding electrons.

**Part C**

Determine the molecular geometry around each interior nitrogen atom that this molecule.

**Part D**

Make a map out of the complying with molecule: N2H4 (skeletal framework H2NNH2).

Draw the molecule by placing atoms on the grid and connecting them v bonds. Include all hydrogen atoms and also nonbonding electrons.

See more: How Many Calories In 100 Grams Of Chicken Breast, Chicken Breast

**Part E**

Determine the molecular geometry around each inner nitrogen atom of this molecule.

ScienceChemistry

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## Answers

Answers #1

First counting the total variety of valence electrons in N, as follows: valence electrons in N,- 2x(5) 10 Next draw the skeletal framework of N2 presented as follows: N-N There room 2 valence electron in the over structure, so the staying valence electrons space 8. So, complete octet because that nitrogen atoms by placing 4 valence electrons together lone pairs on every nitrogen. Therefore, the final Lewis structure of N2 is as follows:

valence electrons in N,H.- 2x(5+2x(1) 12 Next draw the skeletal structure of N,H, presented as follows: There space 6 valence electrons in the over structure, so the remaining valence electrons space 6. So, finish octet because that nitrogen atom by put 4 valence electrons as lone pairs on each nitrogen atoms. Therefore, the last Lewis framework of N,H is as follows: for making nitrogen atom together octet, transition two electrons from nitrogen come nitrogen together a dual bond. Therefore, the Lewis framework of N,H, is together follows:

valence electron in N,H,- 2x(5+4x(1) Next draw the skeletal framework of N,H, displayed as follows: There space 10 valence electron in the above structure, for this reason the continuing to be valence electrons room 4. So, finish octet for nitrogen atom by place 2 valence electrons as lone bag on every nitrogen atoms. Therefore, the last Lewis framework of N,H is as follows: Geometryof N,isLinear. Geometry of N.H.isa open publication shape Geometry the N.H, isbent trigonal pyramidal geometry

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