b) based upon your price in component A, calculation the number of atoms in this lot of 13C?

c) based upon your price in component B, how numerous electrons are in this lot of 13C?

______ electrons

d) based on your price in component B, how numerous neutrons room in this amount of 13C?

______ neutrons

a) How many moles that atoms room in 7.00 g the 13C?

1mol 13C has mass = 13g

7.00g 13C has actually mass = 7.00g/13g/mol = 0.538 mol atoms

b) based on your prize in part A, calculation the variety of atoms in this quantity of 13C?

1mol of atom of any kind of element has 6.022*10^23 atoms

0.538 mol will certainly contain 0.538*6.022*10^23 = 3.24*10^23 13C atoms

c) based on your prize in part B, how many electrons room in this amount

of 13C?

Each 13C atoms has actually 6 electrons

Number of electrons = 6*3.24*10^23 = 1.94*10^24 electrons.

You are watching: How many neutrons are in this amount of 13c

d) based upon your price in component B, how countless neutrons are in this lot of 13C?

13C method that the atom includes 6 proton , 6 electrons and also 7 neutrons

Number of neutrons = 7* 3.24*10^23 = 2.27*10^24 neutrons.

a) How countless moles that atoms space in 7.00 g the 13C?

( 7.00g /13.00g mol⁻¹ )

= 0.538 mol the carbon-13

━━━━━━━━━━━

b) based on your answer in component A, calculation the variety of atoms in this quantity of 13C?

( 6.022 x 10²³ atom / mol ) ( 0.538 mol that carbon-13 )

= 3.24 x 10²³ atom of carbon-13

━━━━━━━━━━━━━━━

c) based upon your price in part B, how plenty of electrons room in this amount of 13C?

( 6 electron / atom ) ( 3.24 x 10²³ atoms of carbon-13 )

= 1.95 x 10²⁴ electrons

━━━━━━━━━━

d) based on your prize in component B, how plenty of neutrons room in this quantity of 13C?

( 7 neutron / atom ) ( 3.24 x 10²³ atoms of carbon-13 )

= 2.27 x 10²⁴ neutrons

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