(NH4)2CO3 : (NH4)+
1 : 2
0.07 = 2× 0.07 = 0.14 mol
Result;Thus 0.14 mol of ammonium ions will certainly be developed .
You are watching: How many moles of ammonium ions are in 6.955 g of ammonium carbonate?
The formula the ammonium carbonate is (NH4)2CO3
so as presented in the formula there are two moles of ammonium ion in each mole the ammonium carbonate .
Given : mass of ammonium lead carbonate = 6.955g
Molar fixed of ammonium carbonate = 96 g / mol
Moles = fixed / molar mass = 6.955 / 96 = 0.072 moles
So mole of ammonium ion = 2 X mole of ammonium lead carbonate
= 2X 0.072 = 0.144 moles
If 10.7 grams of NH4Cl is dissolved in sufficient water to do 800 mL the solution,what will be it"s molarity
1- Molar solutions: based on number of moles of chemistry in 1 litre that solution
2- load % solution: the weight of chemical divided by the complete weight the the solution (chemical + water) and multiplied by 100.
A molecule comprise a main atom through sp2 hybridization has actually a(n) __________ electron geometry.A. BentB. TetrahedralC. Linear
mmsanotherstage2019.com: E. Trigonal planar
The trigonal planar geometry is comprised of 3 equally spaced sp2 hybrid orbitals arranged at edge 120° to every other, The molecule space electron deficient and does not follow octet rule. Therefore, a molecule comprise an sp2 hybrid main atom has actually a trigonal planar geometry e.g boron hydride (BH3)
Compute the power separation between the floor and third excited claims for an electron in a one-dimensional crate that is 5.60
35.51 × 10^-17 KJ/mol
We deserve to calculate this utilizing the Planck"s equation:
E = hc/λ
Where E is the power separation
h is the planck"s constant with a value 6.63 × 10^-34 m^2kg/s
c is the rate of light through value 3 × 10^8m/s
λ is the wavelength v value 5.60Å. 1 Å = 10^-10 m. Thus , 5.60Å is 0.56 × 10^-9nm.
We plug the worths in the equation:
E = (6.63 × 10^-34 × 3 x 10^8)/ 0.56 × 10^-9 = 35.51 × 10^-17KJ
because that Planck"s continuous (h) and 3 × 108 m/s because that the speed of irradiate (c)
1 Å = 10-10 m
6 months ago
In the adhering to reaction, how many moles the FeO are essential to react completely with 1.6 mol that Al? 1.2 1.8 2.4 3.0
I’m notSure i’m sorry
5 months ago
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