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You are watching: Factor 4x^2-4x+1



move all terms no containing `x` to the right-hand next of the equation.

`4x^2-4x = -1`

To set the left-hand next of the equation equal to `0` , move all the expression to the left-hand side.

`4x^2-4x+1=0`

Remove the fraction by multiplying the an initial term that the element by...


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Move all terms not containing `x` come the right-hand next of the equation.

`4x^2-4x = -1`

To set the left-hand next of the equation same to `0` , relocate all the expression to the left-hand side.

`4x^2-4x+1=0`

Remove the fraction by multiplying the an initial term the the variable by the denominator that the second term. `(2x-1)(2x-1)=0` collection each the the factors of the left-hand side of the equation equal to `0` . `2x-1=0` since `-1` does not contain the change to resolve for, move it to the right-hand next of the equation by including `1` to both sides. `2x=1` division each hatchet in the equation by `2` .

`x=1/2`


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baxthum8
Educator because 2013

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Factor: `4x^2 = 4 x-1`

`4x^2-4x + 1 = 0`

`(2x - 1)(2x-1) = 0`

The source is x = `1/2.`


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Tushar Chandra
Educator due to the fact that 2010

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The equation 4x^2 = 4x - 1 has to be resolved for x.

Write the equation in the standard form of a quadratic equation ax^2 + bx + c = 0

4x^2 = 4x - 1

=> 4x^2 - 4x + 1 = 0

The polynomial 4x^2 - 4x + 1 has to be factored and also each the them equated to 0 to determine the root.

See more: A Ventilation Blower Should Be Operated For How Long After Fueling?

4x^2 - 4x + 1 = 0

Notice that 4x^2 = (2x)^2 and 4x = 2*2x*1. Substituting the very same gives: (2x)^2 - 2*2x*1 + 1^2 = 0

The left hand side is in the type a^2 - 2*a*b + b^2 i beg your pardon is equal to (a - b)^2

4x^2 - 4x + 1 = 0

=> (2x - 1)^2 = 0

=> x = 1/2

The solution of the equation 4x^2 = 4x - 1 is x = 1/2


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